By | 25.12.2016

# Convert Decimal Number to Binary

Write a C++ Program to Convert Decimal Number to Binary. Here’s simple C++ Program to Convert Decimal Number to Binary Programming Language.

## Numbers in C++

Normally, when we work with Numbers, we use primitive data types such as int, short, long, float and double, etc. The number data types, their possible values and number ranges have been explained while discussing C++ Data Types.

Here is source code of the C++ Program to Convert Decimal Number to Binary. The C++ program is successfully compiled and run(on Codeblocks) on a Windows system. The program output is also shown in below.

### SOURCE CODE : :

/*  C++ Program to Convert Decimal Number to Binary  */

#include<iostream>

using namespace std;

int main()
{
int d,n,i,j,a[50];
cout<<"Enter any Decimal number :: ";
cin>>n;

cout<<"\nThe binary conversion of [ "<<n<<" ] is 1";

for(i=1;n!=1;++i)
{
d=n%2;
a[i]=d;
n=n/2;
}

for(j=i-1;j>0;--j)
cout<<a[j];

return 0;
}

### OUTPUT : :

/*  C++ Program to Convert Decimal to Binary  */

Enter any Decimal number :: 1234

The binary conversion of [ 1234 ] is 10011010010

Process returned 0

Above is the source code for C++ Program to Convert Decimal to Binary which is successfully compiled and run on Windows System.The Output of the program is shown above .

If you found any error or any queries related to the above program or any questions or reviews , you wanna to ask from us ,you may Contact Us through our contact Page or you can also comment below in the comment section.We will try our best to reach up to you in short interval.

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My name is Tunde Ajetomobi, a Tech Enthusiast and Growth Hacker. I enjoy creating helpful content that solves problem across different topics. Codezclub is my way of helping young aspiring programmers and students to hone their skills and find solutions on fundamental programming languages.

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#include <iostream>
#include <cmath>
using namespace std;

int main()
{
// convert number from decimal to binary.
// 35 -> 100011.
int dec,bin,j,i,n,k;
cout<<“Decimal :: “;cin>>dec;

for(i=0;i<21;i++)
if(dec<=pow(2,i)&&dec>pow(2,i-1))
{ k=i-1; /*7*/ n=i-1; j=i-1; break; }
int arr[k];

for(k=k;k>=0;k–)
{
if(dec>=pow(2,k))
{
dec = dec – pow(2,k);
arr[n]=1;
}
else
arr[n]=0;
n–;
}

cout<<“binary :: “;
for(j=j;j>=0;j–)
cout<<arr[j];

return 0;
}