C++ Program to Convert Decimal Number to Binary

By | 25.12.2016

Convert Decimal Number to Binary


Write a C++ Program to Convert Decimal Number to Binary. Here’s simple C++ Program to Convert Decimal Number to Binary Programming Language.


Numbers in C++


Normally, when we work with Numbers, we use primitive data types such as int, short, long, float and double, etc. The number data types, their possible values and number ranges have been explained while discussing C++ Data Types.


Here is source code of the C++ Program to Convert Decimal Number to Binary. The C++ program is successfully compiled and run(on Codeblocks) on a Windows system. The program output is also shown in below.


SOURCE CODE : :


/*  C++ Program to Convert Decimal Number to Binary  */

#include<iostream>

using namespace std;

int main()
{
    int d,n,i,j,a[50];
    cout<<"Enter any Decimal number :: ";
    cin>>n;

    cout<<"\nThe binary conversion of [ "<<n<<" ] is 1";

    for(i=1;n!=1;++i)
    {
        d=n%2;
        a[i]=d;
        n=n/2;
    }

    for(j=i-1;j>0;--j)
        cout<<a[j];

    return 0;
}

OUTPUT : :


/*  C++ Program to Convert Decimal to Binary  */

Enter any Decimal number :: 1234

The binary conversion of [ 1234 ] is 10011010010

Process returned 0

Above is the source code for C++ Program to Convert Decimal to Binary which is successfully compiled and run on Windows System.The Output of the program is shown above .

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About Tunde A

My name is Tunde Ajetomobi, a Tech Enthusiast and Growth Hacker. I enjoy creating helpful content that solves problem across different topics. Codezclub is my way of helping young aspiring programmers and students to hone their skills and find solutions on fundamental programming languages.

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aswany.

#include <iostream>
#include <cmath>
using namespace std;

int main()
{
  // convert number from decimal to binary.
  // 35 -> 100011.
  int dec,bin,j,i,n,k;
  cout<<“Decimal :: “;cin>>dec;
   
  for(i=0;i<21;i++)
    if(dec<=pow(2,i)&&dec>pow(2,i-1))
    { k=i-1; /*7*/ n=i-1; j=i-1; break; }
   int arr[k];
   
  for(k=k;k>=0;k–)
  {
    if(dec>=pow(2,k))
    {
      dec = dec – pow(2,k);
      arr[n]=1;
    }
    else
      arr[n]=0;
    n–;  
  }
   
  cout<<“binary :: “;
  for(j=j;j>=0;j–)
    cout<<arr[j];
   
 
  return 0;
}