Java program to find Reverse of a number

Java Program to reverse a number in Java Programming, you have to ask to the user to enter the number.

Start reversing the number, first make a variable rev and place 0 to rev initially, and make one more variable say rem.

Now place the modulus of the number to rem and place rev*10+rem to the variable rev, now divide the number with 10 and continue until the number will become 0.

SOURCE CODE ::

import java.util.Scanner;
 
public class Reverse_Number
{
   public static void main(String args[])
   {
      int n, reverse = 0;
 
      System.out.println("Enter the number to reverse");
      Scanner in = new Scanner(System.in);
      n = in.nextInt();
 
      while( n != 0 )
      {
          reverse = reverse * 10;
          reverse = reverse + n%10;
          n = n/10;
      }
 
      System.out.println("Reverse of entered number is "+reverse);
   }
}

OUTPUT ::

Enter the number to reverse
12345
Reverse of entered number is 54321