C Program for Traversing Undirected Graph through DFS Recursively

By | 29.06.2017

Traversing Undirected Graph through DFS Recursively


Write a C Program for Traversing Undirected Graph through DFS Recursively. Here’s simple Program for Traversing an Undirected Graph through DFS Recursively in C Programming Language.


Depth First Search (DFS)


Depth First Search (DFS) algorithm traverses a graph in a depthward motion and uses a stack to remember to get the next vertex to start a search, when a dead end occurs in any iteration.

It employs the following rules.

  • Rule 1 − Visit the adjacent unvisited vertex. Mark it as visited. Display it. Push it in a stack.
  • Rule 2 − If no adjacent vertex is found, pop up a vertex from the stack. (It will pop up all the vertices from the stack, which do not have adjacent vertices.)
  • Rule 3 − Repeat Rule 1 and Rule 2 until the stack is empty.

We shall not see the implementation of Depth First Traversal (or Depth First Search) in C programming language


Also Read : : C Program for Traversing Directed Graph through DFS and classifying all edges

Below is the source code for C Program for Traversing Undirected Graph through DFS Recursively in output which is successfully compiled and run on Windows System to produce desired output as shown below :


SOURCE CODE : :


/* C Program for Traversing Undirected Graph through DFS Recursively */

#include<stdio.h>
#define MAX 100

#define initial 1
#define visited 2
#define finished 3

int adj[MAX][MAX];

int n;    /* Denotes number of vertices in the graph */

int state[MAX];
int predecessor[MAX];

void create_graph();
void DFS(int v);
void DF_Traversal();

int main()
{
        create_graph();
        DF_Traversal();
        return 0;
}/*End of main()*/

void DF_Traversal()
{
        int v;
        for(v=0; v<n; v++)
        {
                state[v] = initial;
                predecessor[v] = -1;
        }
        printf("\nEnter starting vertex for Depth First Search : ");
        scanf("%d",&v);
        DFS(v);
        for(v=0; v<n; v++)
        {
                if(state[v] == initial)
                        DFS(v);
        }
}/*End of DF_Traversal()*/

void DFS(int v)
{
        int i;
        state[v] = visited;
        printf("%d  ",v);
        for(i=0; i<n; i++)
        {
                if(adj[v][i] == 1)
                {
                        if(state[i] == initial)
                                DFS(i);
                }
        }
        state[v] = finished;
}/*End of DFS()*/


void create_graph()
{
        int i,max_edges,origin,destin;

        printf("Enter number of vertices : ");
        scanf("%d",&n);
        max_edges = n*(n-1)/2;

        for(i=1; i<=max_edges; i++)
        {
                printf("\nEnter edge %d( -1 -1 to quit ) : ",i);
                scanf("%d %d",&origin,&destin);

                if( (origin == -1) && (destin == -1) )
                        break;

                if( origin >= n || destin >= n || origin<0 || destin<0)
                {
                        printf("\nInvalid edge!\n");
                        i--;
                }
                else
                {
                        adj[origin][destin] = 1;
                        adj[destin][origin] = 1;
                }
        }
}

OUTPUT : :


/* C Program for Traversing Undirected Graph through DFS Recursively */

Enter number of vertices : 6

Enter edge 1( -1 -1 to quit ) : 0 1

Enter edge 2( -1 -1 to quit ) : 0 2

Enter edge 3( -1 -1 to quit ) : 0 3

Enter edge 4( -1 -1 to quit ) : 2 4

Enter edge 5( -1 -1 to quit ) : 3 5

Enter edge 6( -1 -1 to quit ) : 1 5

Enter edge 7( -1 -1 to quit ) : -1 -1

Enter starting vertex for Depth First Search : 0
0  1  5  3  2  4

Process returned 0

If you found any error or any queries related to the above program or any questions or reviews , you wanna to ask from us ,you may Contact Us through our contact Page or you can also comment below in the comment section.We will try our best to reach up to you in short interval.


Thanks for reading the post…


Recommended Posts : :

0 0 votes
Article Rating
Subscribe
Notify of
guest

0 Comments
Inline Feedbacks
View all comments