*Sum of series S=1+(1+2)+(1+2+3)+..….+(1+2+3+…+n)*

Write a C program to find Sum of series S=1+(1+2)+(1+2+3)+..….+(1+2+3+…+n).This program calculates the sum of series upto n i.e user input and produce result.

In this C Program, Firstly we are going to take input integer ‘n’ from the user and then starts loops starting from 1 to n and calculate sum for each iteration.After that just print the result i.e sum as output on the screen.

Here, the C program to find Sum of series S=1+(1+2)+(1+2+3)+..….+(1+2+3+…+n) is successfully compiled and run on the windows system and produces the output as shown below for different input i.e n. Let’s check out this C Program shown below : :

**SOURCE CODE : :**

**SOURCE CODE : :**

/* C program to find Sum of series S=1+(1+2)+(1+2+3)+..….+(1+2+3+…+n) */ #include<stdio.h> int main() { int n,sum,sum1=0,i,j; printf("\nEnter value for n = "); scanf("%d",&n); for(i=1;i<=n;i++) { sum=0; for(j=1;j<=i;j++) { sum=sum+j; } sum1=sum1+sum; } printf("\nThe Sum of Series up to Value [ %d ] = [ %d ]\n",n,sum1); return 0; }

**OUTPUT : :**

**OUTPUT : :**

/* C program to find Sum of series S=1+(1+2)+(1+2+3)+..….+(1+2+3+…+n) */ Enter value for n = 10 The Sum of Series up to Value [ 10 ] = [ 220 ] Process returned 0

Above is the source code for C program to find Sum of series S=1+(1+2)+(1+2+3)+..….+(1+2+3+…+n) which is successfully compiled and run on Windows System.The Output of the program is shown above .

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Can you explain the program

pls explain the program

/! You can use one loop to do it

using namespace std;

#include

int main()

{

int i,n,s,ts;

s=ts=0;

cin>>n;

for(i=1;i<=n;i++)

{

s=s+i;

ts=ts+s;

}

cout<<ts;

}