By | 05.11.2016

# Sum of Series: 1/1!+2/2!+3/3!+4/4!+….+N/N!

Write a C Program to find the sum of Series: 1/1!+2/2!+3/3!+4/4!+….+N/N!. Here’s simple C Program to find the sum of Series: 1/1!+2/2!+3/3!+4/4!+….+N/N!in C Programming Language.

## Numbers in C

Normally, when we work with Numbers, we use primitive data types such as int, short, long, float and double, etc. The number data types, their possible values and number ranges have been explained while discussing C Data Types.

Here is source code of the C Program to find the sum of Series: 1/1!+2/2!+3/3!+4/4!+….+N/N!. The C program is successfully compiled and run(on Codeblocks) on a Windows system. The program output is also shown in below.

### SOURCE CODE : :

```/*   C Program to find the sum of Series: 1/1!+2/2!+3/3!+4/4!+....+N/N!  */

#include<stdio.h>

/*function to find factorial of the number*/
unsigned long factorial(int num)
{
int i;
/*always assign 1, if variable multiplies with values*/
unsigned long fact=1;

/*multiply num*num-1*num-2*..1*/
for(i=num; i>=1; i--)
fact= fact*i;

/*return factorial*/
return fact;
}

int main()
{
int i,N;
float sum;

printf("\nEnter the value of N :: ");
scanf("%d",&N);

/*set sum by 0*/
sum=0.0f;

/*calculate sum of the series*/
for(i=1;i<=N;i++)
sum = sum + ( (float)(i) / (float)(factorial(i)) );

/*print the sum*/

printf("\nSum of the series is :: %f\n",sum);

return 0;
}```

### OUTPUT : :

```/*   C Program to find the sum of Series: 1/1!+2/2!+3/3!+4/4!+....+N/N!  */

Enter the value of N :: 20

Sum of the series is :: 2.718282

Process returned 0```

Above is the source code for C Program to find the sum of Series: 1/1!+2/2!+3/3!+4/4!+….+N/N! which is successfully compiled and run on Windows System.The Output of the program is shown above .

If you found any error or any queries related to the above program or any questions or reviews , you wanna to ask from us ,you may Contact Us through our contact Page or you can also comment below in the comment section.We will try our best to reach up to you in short interval. 