Display array with addresses using pointers
Write a C Program to display array with addresses using pointers. Here’s simple Program to display array with addresses using pointers in C Programming Language.
What are Pointers?
A pointer is a variable whose value is the address of another variable, i.e., direct address of the memory location. Like any variable or constant, you must declare a pointer before using it to store any variable address.
The general form of a pointer variable declaration is −
- type *var-name;
Here, type is the pointer’s base type; it must be a valid C data type and var-name is the name of the pointer variable.
The asterisk * used to declare a pointer is the same asterisk used for multiplication. However, in this statement the asterisk is being used to designate a variable as a pointer.
The unary or monadic operator & gives the “address of a variable’”.
The indirection or dereference operator * gives the “contents of an object pointed to by a pointer”.
Below is the source code for C Program to display array with addresses using pointers which is successfully compiled and run on Windows System to produce desired output as shown below :
SOURCE CODE : :
/* C Program to display array with addresses using pointers */ #include<stdio.h> #include<stdlib.h> #define size 10 int main() { int a[3] = { 11, 22, 33 }; printf("\n a[0] ,value=%d : address=%u", a[0], &a[0]); printf("\n a[1] ,value=%d : address=%u", a[1], &a[1]); printf("\n a[2] ,value=%d : address=%u", a[2], &a[2]); return (0); }
Output : :
/* C Program to display array with addresses using pointers */ a[0] ,value=11 : address=6356740 a[1] ,value=22 : address=6356744 a[2] ,value=33 : address=6356748 Process returned 0
Above is the source code for C Program to display array with addresses using pointers which is successfully compiled and run on Windows System.The Output of the program is shown above .
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