C Program to check whether number is divisible by 11 and 9 or not

Write a C Program to check whether number is divisible by 11 and 9 or not by recursion. Here’s simple Program that tests whether a number is divisible by 11 and 9 or not using Recursion in C Programming Language.

Recursion : :

Recursion is the process of repeating items in a self-similar way. In programming languages, if a program allows you to call a function inside the same function, then it is called a recursive call of the function.

The C programming language supports recursion, i.e., a function to call itself. But while using recursion, programmers need to be careful to define an exit condition from the function, otherwise it will go into an infinite loop.

Recursive functions are very useful to solve many mathematical problems, such as calculating the factorial of a number, generating Fibonacci series, etc.

Below is the source code for C Program to check number is divisible by 11 and 9 using recursion which is successfully compiled and run on Windows System to produce desired output as shown below :

SOURCE CODE : :

/* Program that tests whether a number is divisible by 11 and 9 or not */


#include<stdio.h>
int divisibleBy9(long int x);
int divisibleBy11(long int x);

int main( )
{
        long int num;
        printf("Enter the number to be tested : ");
        scanf("%ld", &num);

        if(divisibleBy9(num))
                printf("\nThe number is divisible by 9\n");
        else
                printf("\nThe number is not divisible by 9\n");

        if(divisibleBy11(num))
                printf("\nThe number is divisible by 11\n");
        else
                printf("\nThe number is not divisible by 11\n");

                return 0;

}/*End of main()*/

int divisibleBy9( long int n )
{
        int sumofDigits;
        if(n==9)
                return 1;
        if(n<9)
                return 0;
        sumofDigits=0;
        while(n>0)
        {
                sumofDigits += n%10;
                n/=10;
        }
        divisibleBy9(sumofDigits);
}/*End of divisibleBy9()*/

int divisibleBy11( long int n )
{
        int s1=0, s2=0,diff;

        if(n == 0)
                return 1;
        if(n < 10)
                return 0;

        while(n>0)
        {
                s1 += n%10;
                n /=10;
                s2 += n%10;
                n /= 10;
        }
        diff = s1>s2 ? (s1-s2) : (s2-s1);
        divisibleBy11(diff);
}/*End of divisibleBy11()*/

OUTPUT : :

***************OUTPUT***************


***************FIRST RUN************

Enter the number to be tested : 6534

The number is divisible by 9

The number is divisible by 11



***************SECOND RUN************

Enter the number to be tested : 657

The number is divisible by 9

The number is not divisible by 11



***************THIRD RUN************

Enter the number to be tested : 742

The number is not divisible by 9

The number is not divisible by 11

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