LCM of two numbers using functions

Write a C++ program to find LCM of two numbers using functions. Here’s simple program to find LCM of two numbers using functions in C++ Programming Language.

A common multiple is a number that is a multiple of two or more numbers. The common multiples of 3 and 4 are 0, 12, 24, ….

The least common multiple (LCM) of two numbers is the smallest number (not zero) that is a multiple of both.

Here is source code of the C++ program to find LCM of two numbers using functions. The C++ program is successfully compiled and run(on Codeblocks) on a Windows system. The program output is also shown in below.

SOURCE CODE : :

/*  C++ program to find LCM of two numbers using functions  */

#include<iostream>
using namespace std;

void lcm(int,int);

int main()
{
    int a,b;

    cout<<"Enter 1st number :: ";
    cin>>a;
    cout<<"\nEnter 2nd number :: ";
    cin>>b;

    lcm(a,b);

  return 0;
}

//function to calculate l.c.m
void lcm(int a,int b)
{
    int m,n;

    m=a;
    n=b;

    while(m!=n)
    {
        if(m < n)
        {
        m=m+a;
        }
        else
        {
            n=n+b;
            }
    }

    cout<<"\nL.C.M of [ "<<a<<" ] and [ "<<b<<" ] is :: "<<m<<"\n";
}

Output : :

/*  C++ program to find LCM of two numbers using functions  */

Enter 1st number :: 2

Enter 2nd number :: 15

L.C.M of [ 2 ] and [ 15 ] is :: 30

Process returned 0

Above is the source code for C++ program to find LCM of two numbers using functions which is successfully compiled and run on Windows System.The Output of the program is shown above .

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Dave

1 year ago

#include <iostream>
using namespace std;

int LCM(int a, int b){
int a1, m, i=2;

while(m!=0){
a1=a*i;
m=a1%b;
i++;
}

return a1;

}

int main(){
int a, b;

cout << “Enter number 1: “; //El usuario ingresa una cifra
cin >> a;

cout << “Enter number 2: “; // El usuario ingresa otra cifra
cin >> b;

cout << LCM(a,b);

}

Nabeel Tiwana

#include <bits/stdc++.h>

using namespace std;

  int lcm(int a,int b)
  {
      int ans,max;
      max=(a>b)?a:b;
      for(int i=max;i<=a*b;i+=max)
      {
        if((i%a==0)&&(i%b==0))
        {
          ans=i;
          break;
        }

      }
      return ans;
  }

  int main()
  {
    int a,b;
    cout<<“Enter first number:”;
    cin>>a;
    cout<<“Enter second number:”;
    cin>>b;
    cout<<lcm(a,b);
    cout<<endl;

return 0;
}