C Program to Print Ancestors of a given node in Binary Search Tree

By | 01.05.2017

Print Ancestors of Binary Search Tree 


Write a C Program to Print Ancestors of a given node in Binary Search Tree. Here’s simple Program to Print Ancestors of a given Binary Tree in C Programming Language.


What is Tree ?


In linear data structure, data is organized in sequential order and in non-linear data structure, data is organized in random order. Tree is a very popular data structure used in wide range of applications.

A tree data structure can be defined as follows…

  • Tree is a non-linear data structure which organizes data in hierarchical structure and this is a recursive definition.

A tree data structure can also be defined as follows…

  • Tree data structure is a collection of data (Node) which is organized in hierarchical structure and this is a recursive definition.

Every individual element is called as Node. Node in a tree data structure, stores the actual data of that particular element and link to next element in hierarchical structure.


Below is the source code for C Program to Print Ancestors of a given node in Binary Search Tree which is successfully compiled and run on Windows System to produce desired output as shown below :


SOURCE CODE : :


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/* C Program to Print Ancestor of a given node in Binary Search Tree  */

 

#include<stdio.h>

#include<stdlib.h>

#define MAX 100

 

struct node

{

struct node *lchild;

int info;

struct node *rchild;

};

 

 

struct node *insert(struct node *ptr, int ikey);

void display(struct node *ptr,int level);

void DisplayAncestors(struct node *root, int item);

 

int main()

{

struct node *root=NULL,*ptr;

int choice,k,item;

 

while(1)

{

printf(“\n”);

printf(“1.Insert\n”);

printf(“2.Display\n”);

printf(“3.Print Ancestors\n”);

printf(“4.Quit\n”);

printf(“\nEnter your choice : “);

scanf(“%d”,&choice);

 

switch(choice)

{

 

case 1:

printf(“\nEnter the key to be inserted : “);

scanf(“%d”,&k);

root = insert(root, k);

break;

 

        case 2:

            printf(“\n”);

            display(root,0);

            printf(“\n”);

            break;

 

        case 3:

            printf(“\nEnter an item whose Ancestors to be displayed :: “);

            scanf(“%d”,&item);

            printf(“\nAncestors of [ %d ] are :: “,item);

            DisplayAncestors(root, item);

            printf(“\n”);

            break;

 

        case 4:

exit(1);

 

default:

printf(“\nWrong choice\n”);

 

}/*End of switch */

}/*End of while */

 

return 0;

 

}/*End of main( )*/

 

 

struct node *insert(struct node *ptr, int ikey )

{

if(ptr==NULL)

{

ptr = (struct node *) malloc(sizeof(struct node));

ptr->info = ikey;

ptr->lchild = NULL;

ptr->rchild = NULL;

}

else if(ikey < ptr->info) /*Insertion in left subtree*/

ptr->lchild = insert(ptr->lchild, ikey);

else if(ikey > ptr->info) /*Insertion in right subtree */

ptr->rchild = insert(ptr->rchild, ikey);

else

printf(“Duplicate key\n”);

return(ptr);

}/*End of insert( )*/

 

void display(struct node *ptr,int level)

{

int i;

if(ptr == NULL )/*Base Case*/

return;

else

    {

display(ptr->rchild, level+1);

printf(“\n”);

for (i=0; i<level; i++)

printf(”    “);

printf(“%d”, ptr->info);

display(ptr->lchild, level+1);

}

}/*End of display()*/

 

 

void DisplayAncestors(struct node *ptr, int item)

{

if( ptr == NULL  || ptr->info==item )

return;

if( item < ptr->info )

DisplayAncestors(ptr->lchild, item);

else

DisplayAncestors(ptr->rchild, item);

printf(” %d “,ptr->info);

}/*End of DisplayAncestors()*/


OUTPUT : :


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/* C Program to Print Ancestor of a given node in Binary Search Tree  */

 

1.Insert

2.Display

3.Print Ancestors

4.Quit

 

Enter your choice : 1

 

Enter the key to be inserted : 3

 

1.Insert

2.Display

3.Print Ancestors

4.Quit

 

Enter your choice : 1

 

Enter the key to be inserted : 2

 

1.Insert

2.Display

3.Print Ancestors

4.Quit

 

Enter your choice : 1

 

Enter the key to be inserted : 1

 

1.Insert

2.Display

3.Print Ancestors

4.Quit

 

Enter your choice : 1

 

Enter the key to be inserted : 0

 

1.Insert

2.Display

3.Print Ancestors

4.Quit

 

Enter your choice : 2

 

 

3

    2

        1

            0

 

1.Insert

2.Display

3.Print Ancestors

4.Quit

 

Enter your choice : 1

 

Enter the key to be inserted : 4

 

1.Insert

2.Display

3.Print Ancestors

4.Quit

 

Enter your choice : 1

 

Enter the key to be inserted : 5

 

1.Insert

2.Display

3.Print Ancestors

4.Quit

 

Enter your choice : 1

 

Enter the key to be inserted : 6

 

1.Insert

2.Display

3.Print Ancestors

4.Quit

 

Enter your choice : 1

 

Enter the key to be inserted : 7

 

1.Insert

2.Display

3.Print Ancestors

4.Quit

 

Enter your choice : 1

 

Enter the key to be inserted : 8

 

1.Insert

2.Display

3.Print Ancestors

4.Quit

 

Enter your choice : 1

 

Enter the key to be inserted : 9

 

1.Insert

2.Display

3.Print Ancestors

4.Quit

 

Enter your choice : 2

 

 

                        9

                    8

                7

            6

        5

    4

3

    2

        1

            0

 

1.Insert

2.Display

3.Print Ancestors

4.Quit

 

Enter your choice : 3

 

Enter an item whose Ancestors to be displayed :: 0

 

Ancestors of [ 0 ] are ::  1  2  3

 

1.Insert

2.Display

3.Print Ancestors

4.Quit

 

Enter your choice : 3

 

Enter an item whose Ancestors to be displayed :: 9

 

Ancestors of [ 9 ] are ::  8  7  6  5  4  3

 

1.Insert

2.Display

3.Print Ancestors

4.Quit

 

Enter your choice : 2

 

 

                        9

                    8

                7

            6

        5

    4

3

    2

        1

            0

 

1.Insert

2.Display

3.Print Ancestors

4.Quit

 

Enter your choice : 3

 

Enter an item whose Ancestors to be displayed :: 5

 

Ancestors of [ 5 ] are ::  4  3

 

1.Insert

2.Display

3.Print Ancestors

4.Quit

 

Enter your choice : 4

 

Process returned 1


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